Question 177535
A.)The perimeter of the octagon is the sum of its sides.
{{{P=(x)+(x-2)+(x-3)+(x+5)+(3x-2)+(6)+(2x+8)+2(x+5)}}} 
{{{P=x+x-2+x-3+x+5+3x-2+6+2x+8+2x+10}}}
{{{P=(x+x+x+x+3x+2x+2x)+(-2-3+5-2+6+8+10)}}}
{{{P=11x+22}}}
.
.
.
B.){{{P=11x+22=86}}}
{{{11x=64}}}
{{{x=64/11}}}
.
.
.
Side 1: {{{x=64/11}}}
Side 2: {{{x-2=64/11-22/11=42/11}}}
Side 3: {{{x-3=64/11-33/11=31/11}}}
Side 4: {{{x+5=64/11+55/11=119/11}}}
Side 5: {{{3x-2=3(64/11)-22/11=192/11-22/11=170/11}}}
Side 6: {{{x=6}}}
Side 7: {{{x=2x+8=2(64/11)+88/11=128/11+88/11=216/11}}}
Side 8: {{{x=2(x+5)=2(119/11)=238/11}}}