Question 177449
ok, lets call the 2 numbers a and b
:
Find two numbers whose sum is 65 and such that one is 4 times as large as the other.
:
a+b=65.....eq 1
a=4b.......eq 2
:
take the value of a, which is 4b, from eq 2 and plug it into eq 1
:
4b+b=65
:
5b=65
:
{{{highlight(b=13)}}}
:
{{{highlight(a=4(13)=52)}}}