Question 177433
{{{2/y=(5+1/3)/(8)}}}
OK, first you need to change the mixed number to a fraction.
{{{5+1/3=15/3+1/3=16/3}}}
Now you're equation looks like this
{{{2/y=(16/3)/(8)}}}
You can re-arrange the right hand side,
{{{2/y=(16/3)*(1/8)}}}
And cancel out 8's in the numerator and denominator,
{{{2/y=((2*cross(8))/3)*(1/cross(8))}}}
{{{2/y=2/3}}}
{{{y=3}}}