Question 177424
{{{(4x^(-2)y^(-5))^2=4^2x^(-2*2)y^(-5*2)=16x^(-4)y^(-10)}}} where every term is nonzero.



So {{{(12x^8y^(-7))/(4x^(-2)y^(-5))^2=(12x^8y^-7)/(16x^(-4)y^(-10))}}}



{{{(12x^8y^-7)/(16x^(-4)y^(-10))}}} Start with the given expression.



{{{(3x^8y^-7)/(4x^(-4)y^(-10))}}} Reduce {{{12/16}}} to get {{{3/4}}}



{{{(3x^(8-(-4))y^(-7-(-10)))/4}}} Subtract the corresponding exponents.



{{{(3x^(12)y^(3))/4}}} Subtract



=============================================


Answer:



So {{{(12x^8y^(-7))/(4x^(-2)y^(-5))^2=(3x^(12)y^(3))/4}}} where every term is nonzero.