Question 177301
{{{(x+8)^2-54=0}}} Start with the given equation.



{{{(x+8)^2=54}}} Add 54 to both sides.



{{{x+8=0+-sqrt(54)}}} Take the square root of both sides.



{{{x+8=sqrt(54)}}} or {{{x+8=-sqrt(54)}}} Break up the "plus/minus"



{{{x+8=3*sqrt(6)}}} or {{{x+8=-3*sqrt(6)}}} Simplify the square root.



{{{x=-8+3*sqrt(6)}}} or {{{x=-8-3*sqrt(6)}}} Subtract 8 from both sides.



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Answer:


So the solutions are {{{x=-8+3*sqrt(6)}}} or {{{x=-8-3*sqrt(6)}}}