Question 177274
Take the irrational number {{{sqrt(7)}}} and multiply it by itself {{{sqrt(7)}}} to get 


{{{sqrt(7)*sqrt(7)=sqrt(7*7)=sqrt(49)=7}}}



So {{{sqrt(7)*sqrt(7)=7}}}



So by multiplying {{{sqrt(7)}}} by itself, we took the irrational number and made it into a rational number (7 is rational since {{{7=7/1}}})