Question 177240
First, solve for "x":


{{{x/5-2=x/3}}} Start with the given equation.



{{{15(x/cross(5))-15(2)=15(x/cross(3))}}} Multiply EVERY term by the LCD {{{15}}} to clear the fractions.



{{{3x-30=5x}}} Distribute and multiply.



{{{3x=5x+30}}} Add {{{30}}} to both sides.



{{{3x-5x=30}}} Subtract {{{5x}}} from both sides.



{{{-2x=30}}} Combine like terms on the left side.



{{{x=(30)/(-2)}}} Divide both sides by {{{-2}}} to isolate {{{x}}}.



{{{x=-15}}} Reduce.



Now that we found "x", we can evaluate {{{x^2-2}}}



{{{x^2-2}}} Start with the given expression.



{{{(-15)^2-2}}} Plug in {{{x=-15}}} 



{{{225-2}}} Square -15 to get 225



{{{223}}} Subtract



So {{{x^2-2=223}}} when {{{x=-15}}}