Question 177235
let x = pounds of regular yogurt (3% fat)
let y = pounds of no fat yogurt (0% fat)
60 = pounts of low fat yogurt (1% fat)
you have two simultaneous equations that need top be solved.
they are:
.03 * x + .00 * y = .01 * 60
x + y = 60
from the second formula, you can determine that:
y = 60 - x
the second formula is:
.03 * x + .00 * y = .01 * 60
which becomes:
.03 * x = .01 * 60 because the y cancels out.
divide both sides by .03 to get:
x = (.01*60)/.03 = 20
looks like you need 20 pounds of regular yogurt.
since y = 60 - x, the amount of no fat yogurt required is 40 pounds.
to prove, substitute in the original equation.
.03 * 20 + .00 * 40 = .03 * 60
this becomes:
.6 = .6
equation is true.
value of 20 pounds of regular yogurt mixed with 40 pounds of no fat yogurt is good.
your answer is:
20 pounds of regular yogurt needs to be mixed with 40 pounds of no fat yogurt to get 60 pounds of low fat yogurt.