<PRE><B>Question 177203</B>
Part of $34,000 is invested at an interest rate of 8% and the rest at an interest rate of 10%. if the total interest earned in 1 year was $3000, how much was invested at each rate? 
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Equation:
interext + interest = interest
0.08x + 0.10(34000-x) = 3000
Multiply thru by 100 to get:
8x + 10(34000-x) = 300000
8x + 340000 - 10x = 300000
-2x = -40,000
x = $20,000.00 (amt. invested at 8%)
34000-x = $14,000 (amt. invested at 10%)
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Cheers,
Stan H.</PRE>