Question 177148
Notice how {{{-0.2x^2+12x+11}}} is of the form {{{ax^2+bx+c}}} where {{{a=-0.2}}}, {{{b=12}}}, and {{{c=11}}}



Since {{{a<0}}}, this tells us that the parabola opens down (remember, the coefficient "a" determines whether it opens up or down). So the parabola looks similar to this:


{{{ drawing(500, 500, -10, 10, -10, 10,
 graph( 500, 500, -10, 10, -10, 10,-(x-2)(x-3)+3)

)}}}


Note: this is NOT the graph of {{{-0.2x^2+12x+11}}}, but the parabola opens in the same direction as {{{-0.2x^2+12x+11}}}



So this means that the graph has a maximum.