Question 177111
solve 6x^2 +3x - 18 = 0 using the quadratic formula 
a=6; b=3;c=-18
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x = [-3 +- sqrt(9 - 4*6*-18)]/[2*3]

x = [=3 +- sqrt(441)]/6

x = [-3 +- 21]/6

x = [-3 + 21]/6 or x = [-3 - 21]/6

x = 3 or x = -4
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Cheers,
Stan H.