Question 177067
Let A=area of the original rectangle
x=length of the orig. rectangle
y=width of the orig. rectangle

Then
A=x*y

If the new area is double the orig. rectangle

Then

2*x*y=area of the new rectangle

if you increase one side (let's say the length) by 50%, you are adding x/2
so the new length is x+(x/2)=3x/2

Let W=new width

Then

2*x*y=(3x/2)W
4*x*y=3xW    multiply by 2 both sides
4y=3W     divide both sides by x
W=4y/3=y +(y/3)

1/3 is 33 1/3%.
Therefore, the width is increased by 33 1/3%.

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