Question 177096
Let y = miles driven
and x = days rented
.
Agency A:
CostA = 35x + .24y
.
Agency B:
CostB = 41x + .16y
.
The problem sets x = 3
so:
.
Agency A:
CostA = 35(3) + .24y
CostA = 105 + .24y
.
Agency B:
CostB = 41(3) + .16y
CostB = 123 + .16y
.
Agency B would be better if:
CostB < CostA
123 + .16y < 105 + .24y
.
Solving for y:
123 + .16y < 105 + .24y
123 < 105 + .08y
18 < .08y
18/.08 < y
225 miles < y
.
He has to drive MORE than 225 miles.