Question 177075
*[Tex \large\frac{f(x)}{x+2}=q(x)+\frac{3}{x+2}\]


Use polynomial long division to determine that *[Tex \large\frac{4x+7}{x+2}=4+\frac{-1}{x+2}\]


*[Tex \large\frac{f(x)+4x+7}{x+2}=\frac{f(x)}{x+2}+\frac{4x+7}{x+2}=q(x)+\frac{3}{x+2}+4+\frac{-1}{x+2}=q(x)+4+\frac{2}{x+2}\text{ }\Large\Rightarrow \text{ Remainder }=2\]