Question 177051
{{{h(x)=1/(x+1)}}} Start with the third function.



{{{h(f(x))=1/(3x+1+1)}}} Replace each "x" with {{{3x+1}}}



{{{h(f(x))=1/(3x+2)}}} Combine like terms.



{{{h(f(u(x)))=1/(3*sqrt(x)+2)}}} Replace each "x" with {{{sqrt(x)}}}




So the answer is {{{h(f(u(x)))=1/(3*sqrt(x)+2)}}}