Question 176998
Use the distributive property
{{{(x+6)(x^3-x^2-5x+1) =x(x^3-x^2-5x+1)+6(x^3-x^2-5x+1)}}}
{{{(x+6)(x^3-x^2-5x+1) =(x^4-x^3-5x^2+x)+(6x^3-6x^2-30x+6)}}}
{{{(x+6)(x^3-x^2-5x+1) =x^4+5x^3-11x^2-29x+6}}}