Question 24751
Factor all those pieces to get the following factored forms:
[(2x-3)(x+1)]/[(3x+4)(x+1)]=(2x-3)/(3x+4) and
[(3x+4)(x-5)]/[(2x-3)(2x+3)]

Notice the common factors in the numerator and denominator.
Cancel common factors to get:
 1/[(x-5)(2x+3)]

Cheers,
stan H.