Question 176949
    fIND tHREE CONSECUTIVE EVEN INTERGERS SUCH THAT THE SUM OF THE FIRST AND THIRD IS 90 MORE THAN THE SECOND
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Let x = first consecutive even integer
x+2 = second consecutive even integer
x+4 = third consecutive even integer
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x + (x+4) = (x+2) + 90
2x + 4 = x + 92
x + 4 = 92
x = 88
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The three consecutive even integers are:
88, 90 and 92