Question 176900
{{{2x^2}}} standard equation: y=a(x-h)^2+k....where (h,k) is the vertex
:
line of symmetry is x=h 
:
so h=0 in this equation and k=0
:
vertex is at (0,0) and line of symmetry is x=0
:
{{{graph(300,300,-10,10,-10,10,2x^2)}}}