Question 176901
we know this parabola will open downward as the a is negative. so this will have a maximum
:y=a(x-h)+k.....(h,k) is the vertex
:
axis of symmetry is x=h
:
max min value is y=k
:
{{{y=-x^2+4}}}
:
vertex is at (0,4)
:
line of symmetry is x=0.  line of symmetry is nothing more than the line that splits the parabola in half
:
max is y=4
:
{{{graph(300,300,-10,10,-10,10,-x^2+4)}}}