Question 176901
Please help. Find the vertex, line of symmetry, minimum and maximum value for the quadratic equation. I can do it all after finding the vertex, but I am unsure of how to find it. 
f(x)= 4-x^2
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One Way to find vertex:
Put equation in standard form:
x^2 = -y+4
(x-0)^2 = -(y-4)
Vertex: (0,4)
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Another way to find Vertex:
x= -b/2a = -0/(2*-1) = 0
y = f(0) = 4
Vertex: (0,4)
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Cheers,
Stan H.