Question 176855
{{{a(x-b)/b + 3x = 5c/2}}} SOLVE FOR a 
mult eq by 2b to get rid of the denominators,results:
:
2a(x-b) + 2b(3x) = 5bc
;
2ax - 2ab + 6bx = 5bc
;
2ax - 2ab = 5bc - 6bx
factor out a
a(2x - 2b) = 5bc - 6bx
a = {{{(5bc-6bx)/(2x-2b)}}}
or
a = {{{(b(5c-6x))/(2(x-b))}}}




and then Same problem different SOLVE FOR x 
{{{a(x-b)/b + 3x = 5c/2}}} SOLVE FOR x 
mult eq by 2b to get rid of the denominators,results:
:
2a(x-b) + 2b(3x) = 5bc
;
2ax - 2ab + 6bx = 5bc
;
2ax + 6bx = 5bc + 2ab
factor out x
x(2a + 6b) = 5bc + 2ab
x = {{{(5bc + 2ab)/(2a + 6b)}}}
or
x = {{{(b(5c + 2a))/(2(a + 3b))}}}