Question 176826
Solve for x:
{{{(4^x)(16^(3x-1)) = 8}}} Your first step is good!
{{{(2^(2x))(2^(4(3x-1))) = 2^3}}} Expand the second exponent.
{{{(2^(2x))(2^(12x-4)) = 2^8}}} The second factor on the left shows the exponents being subtracted so this means division:
{{{(2^(2x))((2^(12x))/2^4) = 2^3}}} Multiply both sides by {{{2^4}}}
{{{(2^(2x))(2^(12x)) = (2^3)(2^4)}}} Perform the indicated multiplication by adding the exponents.
{{{2^(14x) = 2^7}}} The bases (2) are equal so the exponents are equal.
{{{14x = 7}}} Divide both sides by 14.
{{{highlight(x = 1/2)}}}