Question 176755
If {{{l}}}= length
If {{{w}}} = width
The perimeter is {{{l + l + w + w}}} or
{{{2l  + 2w}}}
given:
(1) {{{2l + 2w = 44}}} in
(2) {{{w = 3l + 2}}} in
substitute (2) in (1)
{{{2l + 2*(3l + 2) = 44}}}
{{{2l + 6l + 4 = 44}}}
{{{8l = 40}}}
{{{l = 5}}} in
and from (2)
(2) {{{w = 3l + 2}}}
{{{w = 3*5 + 2}}}
{{{w = 17}}} in
The width is 17 in and length is 5 in
check:
(1) {{{2l + 2w = 44}}} in
{{{2*5 + 2*17 = 44}}}
{{{10 + 34 = 44}}}
{{{44 = 44}}}
(2) {{{w = 3l + 2}}} in
{{{17 = 3*5 + 2}}}
{{{17 = 17}}}
OK