Question 176755
the perimeter of a rectangle is 44 inches.find the dimensions if the width is two inches longer than three times the length.then find the area of the rectangle
;
2L + 2W = 44
simplify, divide by 2
L + W = 22
:
It says; the width is two inches longer than three times the length."
The equation for this statement is:
W = 3L + 2
:
substitute (3L+2) for W
L + (3L+2) = 22
4L = 22 - 2
4L = 20
L = {{{20/4}}}
L = 5 in
:
W = 3L + 2
W = 3(5) + 2
W = 17 in
;
find the area: 17 * 5 = 85 sq/in
;
;
check solutions by finding the perimeter
2(5) + 2(17) = 44