Question 176739
let n and d be the number of nickels and dime shankar saved respectively
:
n+d=8..........eq 1
.05n+.1d=.55...eq 2
:
lets re write eq 1 to n=8-d and take that value and plug it into eq 2
:
.05(8-d)+.1d=.55
:
.4-.05d+.1d=.55
:
.05d=.15
:
{{{highlight(d=3)}}}dimes
:
{{{n=8-d}}}.....{{{n=8-3=highlight(5))}}}nickels