Question 176776
Suppose a population of initial size 100 grows at the rate of 8% per year forever. 
What is the size of the population at the end of year 1?
100*(1.08)
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What is the size of the population at the end of year 2?
100(1.08)^2
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What is the size of the population at the end of year 3?
100(1.08)^3
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What is the size of the population at the end of year n (for any integer n)?
100(1.08)^n
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What algebraic equation would you need to solve to find the number of years x that it would take for our population to reach 200? Use a calculator to solve to x.
100(1.08)^n = 200 
1.08^n = 2
n = log(2)/log(1.08) = 9.0064 years
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Cheers,
Stan H.