Question 176744

 ok we know that {{{n^x/n^y=n^(x-y)}}}
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now take a look at
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some specifics {{{3^4/3^2=3^(4-2)=3^2}}}
................{{{3^4/3^3=3^(4-3)=3^1}}}
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and now our special case
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{{{3^4/3^4=3^(4-4)=3^0}}}
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but remember {{{3^4/3^4=1}}}
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therefore any number raised to the zero power = 1