Question 24680
{{{i = sqrt(-1)}}}
{{{x^2 = -16}}}
take the square root of both sides
{{{x = sqrt(-16)}}}
note that {{{sqrt(-16) = sqrt(-1 * 16)}}}
and that equals {{{sqrt(-1) * sqrt(16)}}}
so
{{{x = i * sqrt(16)}}}
{{{x = +- (i * 4)}}}
next problem:
{{{8* x^2 = -2}}}
{{{x^2 = -(1/4)}}}
{{{x = sqrt( -1) * sqrt(1/4)}}}
{{{x = +- (i * (1/2))}}}
next problem:
{{{x^2 = -30}}}
{{{x = sqrt(-30)}}}
{{{x = sqrt(-1) * sqrt(30)}}}
{{{x = +- (i * 5.5)}}}