<PRE><B>Question 176688</B>
h= -0.1d^2+d+1. The height of the volleyball is h metres, and the horizontal distance from Duncan is d metres. What is the maximum height reached by the ball?
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Max occurs when d = -b/2a = -1/(2*-0.1) = -1/-0.2 = 5
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Max height = h(d) = -0.1d^2 + d + 1 
h(5) = -0.1(5)^2 + 5 + 1
h(5) = 3.5
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Cheers,
Stan H.
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