Question 176689
The sum of the squares of two consecutive integers is 265. Find the numbers.
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{{{x^2 + (x+1)^2 = 265}}}
{{{2x^2 + 2x + 1 = 265}}}
{{{2x^2 + 2x - 264 = 0}}}
{{{x^2 + x - 132 = 0}}}
(x-11)*(x+12) = 0
x = 11
x+1 = 12
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x = -12
x+1 = -11
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