Question 176572
225) 
{{{x^2+4x-10}}} does not have simple factors. You can find the factors using the quadratic formula.
{{{x = (-4 +- sqrt( 4^2-4*1*(-10) ))/(2*1) }}}
{{{x = (-4 +- sqrt(16+40 ))/(2) }}}
{{{x = (-4 +- sqrt(56))/(2) }}}
{{{x = -2 +- (1/2)*sqrt(56) }}}

{{{x^2+4x-10=(x-(-2+(1/2)*sqrt(56)))(x-(-2-(1/2)*sqrt(56))) }}}
{{{x^2+4x-10=(x+2-(1/2)*sqrt(56))(x+2+(1/2)*sqrt(56)) }}}
 

226)

{{{2x^2+10x-48=(2x-6)(x+8)}}}