Question 176658
A cyclist traveled at a rate of 32 mph to visit a nearby town. The cyclist 
averaged 10 mph on the return trip. If the round trip took 6.3 hours,
 find the distance to the nearby town.
:
let d = one way distance traveled
:
write time equation time = dist/speed
;
{{{d/32}}} + {{{d/10}}} = 6.3
mult eq by 160 to get rid of the denominators,
160*{{{d/32}}} + 160*{{{d/10}}} = 160(6.3)
results
5d + 16d = 1006
;
21d = 1008
d = {{{1008/21}}}
d = 48 mi
:
:
check solution by finding the total time
48/32 = 1.5
48/10 = 4.8
------------
total = 6.3 hr, confirms our solution