Question 176630
i presume you mean {{{(x-8)^2}}} and {{{x^2}}}
{{{f(x) = x^2 - 6}}}
{{{g(x) = (x-8)^2 - 6}}}
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when x = 0, g(x) = (-8)^2 - 6 = 64 - 6 = 58
when x = 0, f(x) = (0 - 6 = -6
when f(x) = -6, x = 0
when g(x) = -6, x = 8
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one of the general forms of quadratic equation is:
{{{f(x) = a(x - h)^2 + k}}}
or
{{{g(x) = a(x - h)^2 + k}}}
where (h,k) is the vertex which is the turning point of the equation.
with f(x), h was 0 and k was -6
with g(x), h was 8 and k was -6
looks like g(x) was shifted 8 units to the right.
graph of both equations follows:
f(x) is -6 when x = 0
g(x) is 58 when x = 0
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{{{graph(800,400,-5,15,-10,100,(x-8)^2-6,x^2-6)}}}