Question 176631
I am going to assume that is suppose to be 16 % and not 60% since that isnt possible. It has to fall between 8% and 20% solutions for this to work. You cannot mix two percentage mixtures together and get less than the lowest or greater than the highest amounts.  lets call the amount of 20% solution x.
:
.08(12)+.2(x)=.16(12+x)
:
.96+.2x=1.92+.16x
:
.04x=.96
:
{{{highlight(x=24)}}}liters of 20% solution