Question 176576
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{{{6x + y = 2 }}}, EQN 1
{{{y = 3x - 4}}}, EQN 2
Subst EQN 2 in EQN 1:
{{{6x+3x-4=2}}}
{{{9x=2+4=6}}}---->{{{cross(9)x/cross(9)=6/9}}}
{{{highlight(x=2/3)}}}, subst in EQN 2:
{{{y=cross(3)(2/cross(3))-4=2-4}}}
{{{highlight(y=-2)}}}
See graph:
{{{drawing(300,300,-4,4,-6,6,grid(1),graph(300,300,-4,4,-6,6,3x-4,2-6x),blue(circle(2/3,-2,.15)))}}}----->RED>>>>EQN 2; GREEN >>>> EQN 1
Thank you,
Jojo</pre>