Question 24663
(x+6)/5 + (2y-x)/10 = 1
(x+2)/4 + (3y+2)/5 = -3<br>  

to clear the fractions from the first equation all you have to do is multiply the entire equation by 10.  you will end up with:<br>

2(x+6)+(2y-x)=10<br>

simplifying you get<br>

2x+12+2y-x=10
x+2y+12=10
x+2y=-2<br>

to clear the fractions from the secound equation all you have to do is multiply the entire equation by 20. you will end up with<br>

5(x+2)+4(3y+2)=-60<br>

simplifying you get<br>

5x+10+12y+8=-60
5x+12y+18=-60
5x+12y=-78<br>

now we multiply equation 1 by -5 and add the 2 equations together<br>

-5(x+2y=-2)
-5x-10y=10<br>

5x+12y=-78
-5x-10y=10
============
2y=-68
y=-34<br>


now pluging that into equation 2<br>

5x+12(-34)=-78
5x-408=-78
5x=330
x=66<br>

and that is the answer (66,-34)