Question 176533

First, extract the coefficients and the right hand constants to form the matrix:



{{{(matrix(2,3,3,5,7,6,-1,-8))}}}



Multiply Row 1 by {{{1/3}}} to make the pivot 1:


{{{(matrix(2,3,1,5/3,7/3,6,-1,-8))}}}



 Add  -6*Row 1 to Row 2 to get the new Row 2


{{{(matrix(2,3,1,5/3,7/3,0,-11,-22))}}}



Multiply Row 2 by {{{-1/11}}} to make the pivot 1:


{{{(matrix(2,3,1,5/3,7/3,0,1,2))}}}





Add {{{-5/3}}}*Row 2 to Row 1 to replace Row 1:


{{{(matrix(2,3,1,0,-1,0,1,2))}}}



The matrix is now in <font size=4><b>reduced row echelon form</b></font>



If you need more help with row reduction, check out the <a href="http://www.math.odu.edu/~bogacki/lat/">Linear Algebra Toolkit</a>




Since the right hand column is {{{(matrix(2,1,-1,2))}}}, this means that {{{x=-1}}} and {{{y=2}}}