Question 176525
Which is equivalent to 1/25^(1/3) 
= [5^(-2)]^(1/3) = 5^(-2/3)
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a0 5^-6
b) 5^-2/3
c) 5^2/3
d) 5^6 ??
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Which is equivalent to 2^x-3/8^x
= (2^(x-3))/[(2^3)^x]
= (2^[(x-3)-3x] 
= 2^[-2x-3]
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a) 2^-3x-3
b) 2^-2x-3
c) 2^2x-3
d) 2^4x-3

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Cheers,
Stan H.