Question 176459
The image is really hard to see. Does the figure look like this:


<img src="http://i150.photobucket.com/albums/s91/jim_thompson5910/Algebra%20dot%20com/geo3.png">


Note: let me know if any of the labels are off



I'll do the first part to get you going in the right direction:


a)


Prove triangle ADE is congruent to Triangle CBF


Here's a two column proof
<table cellspacing="50">
<th>Statement</th><th>Reason</th>
<tr><td>1. Segment DE is perpendicular to Segment AC</td><td>Given</td></tr>
<tr><td>2. Segment BF is perpendicular to Segment AC</td><td>Given</td></tr>
<tr><td>3. Segment AF = Segment CE</td><td>Given</td></tr>
<tr><td>4. Segment DE = Segment BF</td><td>Given</td></tr>
<tr><td>5. Angle AED is a right angle</td><td>Definition of Perpendicular</td></tr>
<tr><td>6. Angle BFC is a right angle</td><td>Definition of Perpendicular</td></tr>
<tr><td>7. Angle BFC = Angle AED</td><td>All right angles are congruent</td></tr>
<tr><td>8. Segment AF + Segment FC = Segment AC</td><td>Segment Addition Postulate</td></tr> 
<tr><td>9. Segment CE + Segment AE = Segment AC</td><td>Segment Addition Postulate</td></tr>
<tr><td>9. Segment AF + Segment FC = Segment CE + Segment AE</td><td>Substitution</td></tr>
<tr><td>10. Segment AF + Segment FC = Segment AF + Segment AE</td><td>Substitution</td></tr>   
<tr><td>11. Segment FC = Segment AE</td><td>Addition Property of Equality</td></tr>  

<tr><td>12. Triangle ADE = Triangle CBF</td><td>SAS Property of Congruence</td></tr>
</table>