Question 176239
I'm assuming the problem is:
{{{(x+3)/2+5=(3x)/4}}}
So as a first step, we'd like to get rid of all the fractions in the problem.  On the left hand side, we have a denominator of 2, and on the right hand side, 4.  So, the LCM is 4.  Multiplying both sides by 4 results in:
{{{2(x+3)+20=3x}}}
{{{2x+6+20=3x}}}
{{{2x+26=3x}}}
Last, to solve for x, subtract 2x from both sides:
{{{26=x}}}