Question 176462
ok lets call the amount of 20% and 50% solutions a and b respectively
:
a+b=10...........eq 1
.2a+.5b=.3(10)...eq 2
:
rewrite eq 1 to a=10-b and plug this value into eq 2
:
.2(10-b)+.5b=3
:
2-.2b+.5b=3
:
.3b=1
:
{{{highlight(b=3.33)}}}amount of 50% solution
:
{{{highlight(a=10-b=10-3.33=6.67)}}}amount of 20% solution