Question 176455
To solve this problem you need to know a property of quadratic equations with complex roots.  If a+bi is a solution of a quadratic equation, so is a-bi.  So since 3+2i is a solution, 3-2i is also.  Now, since 3+2i is a solution, that means that (x-(3+2i)) is a factor.  Thus (x-(3-2i)) is a factor also.  So if we multiply the two together, we should get our equation.
{{{(x-(3+2i))(x-(3-2i))}}}
{{{x^2-x(3-2i)-x(3+2i)+(3+2i)(3-2i)}}}
{{{x^2-3x+2ix-3x-2ix+9-6i+6i-4i^2}}}
{{{x^2-6x+9-4(-1)}}}
{{{x^2-6x+13}}}
Thus, m=-6.