Question 176436
Note: {{{x^(-2)=1/x^2}}}. In other words, to make the exponent positive, flip the base.


So {{{c^(-5)=1/c^5}}} and {{{d^(-1)=1/d^1=1/d}}}



This means that {{{5c^(-5)d^(-1)=5/(c^5*d)}}}