Question 176427
In the word problem , three consecutive numbers where 3times the first is 4 more than 2 times the second. The answer I came up with is 3z=4+2z+1+z+2.


The real solution to the problem is:

1st #:  z
2nd #:  z + 1
3rd #:  z + 2

3(z) = 2(z + 1) +  4
3z  =  2z + 2 + 4
z  =  6

Numbers are 6, 7, & 8