Question 176427
First: z
Second: z+1
Third: z+2
3*(First)=4+2*(Second)
Now substitute,
{{{3z=4+2*(z+1)}}}
Remember, the second number is (z+1), 2 times that is 2(z+1) or 2z+2.
Also, the third number wasn't mentioned but you had it in your equation???
{{{3z=4+2*(z+1)}}}
Now take this equation and solve for z.
Re-post if you get stuck.