Question 176237
1.{{{2q=7-5p}}}
2.{{{4p-16=q}}}
We can use eq. 2 directly and substitute into eq. 1 to solve for p.
1.{{{2q=7-5p}}}
{{{2(4p-16)=7-5p}}}
{{{8p-32=7-5p}}}
{{{13p=39}}}
{{{highlight(p=3)}}}
From eq. 2,
2.{{{4p-16=q}}}
{{{4(3)-16=q}}}
{{{q=12-16}}}
{{{highlight(q=-4)}}}