Question 176359
{{{f(x)=sqrt(x+1)}}}{{{g(x)=5x-2}}}
:
{{{f(g(x))=sqrt(5x-2+1)=highlight(sqrt(5x-1))}}}--->domain is {{{5x-1>=0}}} {x:x>=1/5}
:
{{{g(f(x))=highlight(5(sqrt(x+1))-2)}}}--->domain is {{{x+1>=0}}} {x:x>=-1}