Question 176340
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Let {{{x}}}=unknown, mixed with face cream that cost 3360.00.
{{{y=12L}}}=face cream that cost 1120.00
{{{highlight(z=x+y=x+12)}}}=resultant mixture of {{{x}}} & {{{y}}} when mixed that cost 1650.00
It follows the eqn when mixed:
{{{(3360/L)(x)+(1120/cross(L))(12cross(L))=(1650/L)*highlight(z)}}}
Subst. highlighted:
{{{(3360/L)(x)+13440=(1650/L)(x+12L)}}}
{{{(3360/L)(x)+13440=(1650/L)(x)+19800}}}
{{{(3360/L)x-(1650)x=19800-13440}}}
{{{(1710/L)(x)=6360}}}
{{{cross(1710/L)(x)/cross(1710/L)=cross(6360)3.72/(cross(1710)/L)}}}
{{{highlight(x=3.72L)}}}, Answer
Check by going back:
{{{3360(3.72)+13440=1650(3.72+12)}}}
{{{12499.20+13440=1650(15.72)}}}
{{{25939.20>=25938.00}}} close enough bec we round off.
Thank you,
Jojo</pre>