Question 176049
Since you did not state the question, I am going to have to assume it is to solve the system of equations.
{{{5x+2y=8}}}
{{{2x-3y=7}}}
I will use the addition method.  I will multiply the first equation by 2 and the second equation by -5.
{{{10x+4y=16}}}
{{{-10x+15y=-35}}}
Now, adding, we get
{{{19y=-19}}}
So y=-1.  To get x, you plug in y=-1 into either equation.
5x+2(-1)=8
5x-2=8
5x=10
x=2
So the solution is (2,-1).